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1110033120047 is a prime number
BaseRepresentation
bin10000001001110011001…
…000010011101100101111
310221010012010011002000112
4100021303020103230233
5121141321434320142
62205535302050235
7143124440561255
oct20116310235457
93833163132015
101110033120047
11398842837645
1215b16ba1997b
13808a25c08b7
143ba23bac5d5
151dd1b702382
hex10273213b2f

1110033120047 has 2 divisors, whose sum is σ = 1110033120048. Its totient is φ = 1110033120046.

The previous prime is 1110033119981. The next prime is 1110033120107. The reversal of 1110033120047 is 7400213300111.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (7400213300111) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1110033120047 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1110033126047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555016560023 + 555016560024.

It is an arithmetic number, because the mean of its divisors is an integer number (555016560024).

Almost surely, 21110033120047 is an apocalyptic number.

1110033120047 is a deficient number, since it is larger than the sum of its proper divisors (1).

1110033120047 is an equidigital number, since it uses as much as digits as its factorization.

1110033120047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 23.

Adding to 1110033120047 its reverse (7400213300111), we get a palindrome (8510246420158).

The spelling of 1110033120047 in words is "one trillion, one hundred ten billion, thirty-three million, one hundred twenty thousand, forty-seven".