1110040013 has 2 divisors, whose sum is σ = 1110040014. Its totient is φ = 1110040012.

The previous prime is 1110039991. The next prime is 1110040093. The reversal of 1110040013 is 3100400111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 718079209 + 391960804 = 26797^2 + 19798^2 .

It is an emirp because it is prime and its reverse (3100400111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1110040013 - 2⁶ = 1110039949 is a prime.

It is a super-3 number, since 3×1110040013³ (a number of 28 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 1110039976 and 1110040003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1110040093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555020006 + 555020007.

It is an arithmetic number, because the mean of its divisors is an integer number (555020007).

Almost surely, 2^1110040013 is an apocalyptic number.

It is an amenable number.

1110040013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1110040013 is an equidigital number, since it uses as much as digits as its factorization.

1110040013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 1110040013 is about 33317.2629878266. The cubic root of 1110040013 is about 1035.4112465639.

Adding to 1110040013 its reverse (3100400111), we get a palindrome (4210440124).

The spelling of 1110040013 in words is "one billion, one hundred ten million, forty thousand, thirteen".