3100400111 has 2 divisors, whose sum is σ = 3100400112. Its totient is φ = 3100400110.

The previous prime is 3100400077. The next prime is 3100400113. The reversal of 3100400111 is 1110040013.

It is a strong prime.

It is an emirp because it is prime and its reverse (1110040013) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3100400111 - 2¹⁰ = 3100399087 is a prime.

It is a super-2 number, since 2×3100400111² = 19224961696577624642, which contains 22 as substring.

It is a Sophie Germain prime.

Together with 3100400113, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 3100400092 and 3100400101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3100400113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1550200055 + 1550200056.

It is an arithmetic number, because the mean of its divisors is an integer number (1550200056).

Almost surely, 2^3100400111 is an apocalyptic number.

3100400111 is a deficient number, since it is larger than the sum of its proper divisors (1).

3100400111 is an equidigital number, since it uses as much as digits as its factorization.

3100400111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 3100400111 is about 55681.2366152190. The cubic root of 3100400111 is about 1458.1624644983.

Adding to 3100400111 its reverse (1110040013), we get a palindrome (4210440124).

The spelling of 3100400111 in words is "three billion, one hundred million, four hundred thousand, one hundred eleven".