Base | Representation |
---|---|
bin | 10000001001110111010… |
… | …011101001100110110111 |
3 | 10221010101000000121200222 |
4 | 100021313103221212313 |
5 | 121141442404432411 |
6 | 2205550244124555 |
7 | 143126251346432 |
oct | 20116723514667 |
9 | 3833330017628 |
10 | 1110103202231 |
11 | 398879354401 |
12 | 15b18b39675b |
13 | 808b3c8a94a |
14 | 3ba2d212819 |
15 | 1dd229474db |
hex | 102774e99b7 |
1110103202231 has 2 divisors, whose sum is σ = 1110103202232. Its totient is φ = 1110103202230.
The previous prime is 1110103202207. The next prime is 1110103202233. The reversal of 1110103202231 is 1322023010111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1110103202231 - 214 = 1110103185847 is a prime.
It is a super-2 number, since 2×11101032022312 (a number of 25 digits) contains 22 as substring.
Together with 1110103202233, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1110103202233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555051601115 + 555051601116.
It is an arithmetic number, because the mean of its divisors is an integer number (555051601116).
Almost surely, 21110103202231 is an apocalyptic number.
1110103202231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110103202231 is an equidigital number, since it uses as much as digits as its factorization.
1110103202231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 1110103202231 its reverse (1322023010111), we get a palindrome (2432126212342).
The spelling of 1110103202231 in words is "one trillion, one hundred ten billion, one hundred three million, two hundred two thousand, two hundred thirty-one".
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