Base | Representation |
---|---|
bin | 10000001001110111110… |
… | …101101000010110101001 |
3 | 10221010101121210011212002 |
4 | 100021313311220112221 |
5 | 121142002200004433 |
6 | 2205551203100345 |
7 | 143126420146535 |
oct | 20116765502651 |
9 | 3833347704762 |
10 | 1110112109993 |
11 | 398883388997 |
12 | 15b1923716b5 |
13 | 808b5a89303 |
14 | 3ba30490bc5 |
15 | 1dd236069e8 |
hex | 10277d685a9 |
1110112109993 has 2 divisors, whose sum is σ = 1110112109994. Its totient is φ = 1110112109992.
The previous prime is 1110112109989. The next prime is 1110112110011. The reversal of 1110112109993 is 3999012110111.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 812796008704 + 297316101289 = 901552^2 + 545267^2 .
It is a cyclic number.
It is not a de Polignac number, because 1110112109993 - 22 = 1110112109989 is a prime.
It is a super-2 number, since 2×11101121099932 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1110112109903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555056054996 + 555056054997.
It is an arithmetic number, because the mean of its divisors is an integer number (555056054997).
Almost surely, 21110112109993 is an apocalyptic number.
It is an amenable number.
1110112109993 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110112109993 is an equidigital number, since it uses as much as digits as its factorization.
1110112109993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4374, while the sum is 38.
The spelling of 1110112109993 in words is "one trillion, one hundred ten billion, one hundred twelve million, one hundred nine thousand, nine hundred ninety-three".
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