1110114011 has 2 divisors, whose sum is σ = 1110114012. Its totient is φ = 1110114010.

The previous prime is 1110113987. The next prime is 1110114013. The reversal of 1110114011 is 1104110111.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1110114011 - 2⁶ = 1110113947 is a prime.

Together with 1110114013, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1110113983 and 1110114001.

It is not a weakly prime, because it can be changed into another prime (1110114013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555057005 + 555057006.

It is an arithmetic number, because the mean of its divisors is an integer number (555057006).

Almost surely, 2^1110114011 is an apocalyptic number.

1110114011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1110114011 is an equidigital number, since it uses as much as digits as its factorization.

1110114011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4, while the sum is 11.

The square root of 1110114011 is about 33318.3734747061. The cubic root of 1110114011 is about 1035.4342537402.

Adding to 1110114011 its reverse (1104110111), we get a palindrome (2214224122).

The spelling of 1110114011 in words is "one billion, one hundred ten million, one hundred fourteen thousand, eleven".