1110131101117 has 2 divisors, whose sum is σ = 1110131101118. Its totient is φ = 1110131101116.

The previous prime is 1110131101031. The next prime is 1110131101127. The reversal of 1110131101117 is 7111011310111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 644992096996 + 465139004121 = 803114^2 + 682011^2 .

It is a cyclic number.

It is not a de Polignac number, because 1110131101117 - 2²³ = 1110122712509 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1110131101094 and 1110131101103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1110131101127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555065550558 + 555065550559.

It is an arithmetic number, because the mean of its divisors is an integer number (555065550559).

Almost surely, 2^{1110131101117} is an apocalyptic number.

It is an amenable number.

1110131101117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1110131101117 is an equidigital number, since it uses as much as digits as its factorization.

1110131101117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21, while the sum is 19.

Adding to 1110131101117 its reverse (7111011310111), we get a palindrome (8221142411228).

The spelling of 1110131101117 in words is "one trillion, one hundred ten billion, one hundred thirty-one million, one hundred one thousand, one hundred seventeen".