Base | Representation |
---|---|
bin | 10000001001111000111… |
… | …110000100110111000111 |
3 | 10221010102221112000210102 |
4 | 100021320332010313013 |
5 | 121142022030214002 |
6 | 2205553122114315 |
7 | 143130040444346 |
oct | 20117076046707 |
9 | 3833387460712 |
10 | 1110131101127 |
11 | 39889307a244 |
12 | 15b1987ab99b |
13 | 808b99a8479 |
14 | 3ba32bd5b5d |
15 | 1dd25108a02 |
hex | 10278f84dc7 |
1110131101127 has 2 divisors, whose sum is σ = 1110131101128. Its totient is φ = 1110131101126.
The previous prime is 1110131101117. The next prime is 1110131101193. The reversal of 1110131101127 is 7211011310111.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1110131101127 - 238 = 835253194183 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1110131101099 and 1110131101108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1110131101117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555065550563 + 555065550564.
It is an arithmetic number, because the mean of its divisors is an integer number (555065550564).
Almost surely, 21110131101127 is an apocalyptic number.
1110131101127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110131101127 is an equidigital number, since it uses as much as digits as its factorization.
1110131101127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 42, while the sum is 20.
Adding to 1110131101127 its reverse (7211011310111), we get a palindrome (8321142411238).
The spelling of 1110131101127 in words is "one trillion, one hundred ten billion, one hundred thirty-one million, one hundred one thousand, one hundred twenty-seven".
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