11102000320121 has 2 divisors, whose sum is σ = 11102000320122. Its totient is φ = 11102000320120.

The previous prime is 11102000320091. The next prime is 11102000320123. The reversal of 11102000320121 is 12102300020111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10799038143721 + 302962176400 = 3286189^2 + 550420^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11102000320121 is a prime.

It is a super-4 number, since 4×11102000320121⁴ (a number of 53 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

Together with 11102000320123, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11102000320096 and 11102000320105.

It is not a weakly prime, because it can be changed into another prime (11102000320123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5551000160060 + 5551000160061.

It is an arithmetic number, because the mean of its divisors is an integer number (5551000160061).

Almost surely, 2^{11102000320121} is an apocalyptic number.

It is an amenable number.

11102000320121 is a deficient number, since it is larger than the sum of its proper divisors (1).

11102000320121 is an equidigital number, since it uses as much as digits as its factorization.

11102000320121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 11102000320121 its reverse (12102300020111), we get a palindrome (23204300340232).

The spelling of 11102000320121 in words is "eleven trillion, one hundred two billion, three hundred twenty thousand, one hundred twenty-one".