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1110212200003 is a prime number
BaseRepresentation
bin10000001001111101110…
…011011100011001000011
310221010122121010021112111
4100021331303130121003
5121142203310400003
62210005140240151
7143132043665254
oct20117563343103
93833577107474
101110212200003
11398924931005
1215b1bb9a0057
1380900731a7a
143ba3d8a6b2b
151dd2c2c7e6d
hex1027dcdc643

1110212200003 has 2 divisors, whose sum is σ = 1110212200004. Its totient is φ = 1110212200002.

The previous prime is 1110212200001. The next prime is 1110212200043. The reversal of 1110212200003 is 3000022120111.

It is a weak prime.

It is an emirp because it is prime and its reverse (3000022120111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1110212200003 - 21 = 1110212200001 is a prime.

It is a super-2 number, since 2×11102122000032 (a number of 25 digits) contains 22 as substring.

Together with 1110212200001, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1110212200001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555106100001 + 555106100002.

It is an arithmetic number, because the mean of its divisors is an integer number (555106100002).

Almost surely, 21110212200003 is an apocalyptic number.

1110212200003 is a deficient number, since it is larger than the sum of its proper divisors (1).

1110212200003 is an equidigital number, since it uses as much as digits as its factorization.

1110212200003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 1110212200003 its reverse (3000022120111), we get a palindrome (4110234320114).

The spelling of 1110212200003 in words is "one trillion, one hundred ten billion, two hundred twelve million, two hundred thousand, three".