Base | Representation |
---|---|
bin | 1010000110001110101010… |
… | …0110011101011010001111 |
3 | 1110022100112121222120011011 |
4 | 2201203222212131122033 |
5 | 2423344131122141333 |
6 | 35340125422510051 |
7 | 2224050111135343 |
oct | 241435246353217 |
9 | 43270477876134 |
10 | 11102131443343 |
11 | 35a0429849a36 |
12 | 12b3801435327 |
13 | 626c076b0575 |
14 | 2a54bb709623 |
15 | 143bd2abc9cd |
hex | a18ea99d68f |
11102131443343 has 2 divisors, whose sum is σ = 11102131443344. Its totient is φ = 11102131443342.
The previous prime is 11102131443341. The next prime is 11102131443371. The reversal of 11102131443343 is 34334413120111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11102131443343 - 21 = 11102131443341 is a prime.
Together with 11102131443341, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11102131443341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5551065721671 + 5551065721672.
It is an arithmetic number, because the mean of its divisors is an integer number (5551065721672).
Almost surely, 211102131443343 is an apocalyptic number.
11102131443343 is a deficient number, since it is larger than the sum of its proper divisors (1).
11102131443343 is an equidigital number, since it uses as much as digits as its factorization.
11102131443343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 11102131443343 its reverse (34334413120111), we get a palindrome (45436544563454).
The spelling of 11102131443343 in words is "eleven trillion, one hundred two billion, one hundred thirty-one million, four hundred forty-three thousand, three hundred forty-three".
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