111022121100041 has 2 divisors, whose sum is σ = 111022121100042. Its totient is φ = 111022121100040.

The previous prime is 111022121099987. The next prime is 111022121100043. The reversal of 111022121100041 is 140001121220111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 105577762210816 + 5444358889225 = 10275104^2 + 2333315^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-111022121100041 is a prime.

It is a super-2 number, since 2×111022121100041² (a number of 29 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 111022121100043, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 111022121099992 and 111022121100019.

It is not a weakly prime, because it can be changed into another prime (111022121100043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55511060550020 + 55511060550021.

It is an arithmetic number, because the mean of its divisors is an integer number (55511060550021).

Almost surely, 2^{111022121100041} is an apocalyptic number.

It is an amenable number.

111022121100041 is a deficient number, since it is larger than the sum of its proper divisors (1).

111022121100041 is an equidigital number, since it uses as much as digits as its factorization.

111022121100041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32, while the sum is 17.

Adding to 111022121100041 its reverse (140001121220111), we get a palindrome (251023242320152).

The spelling of 111022121100041 in words is "one hundred eleven trillion, twenty-two billion, one hundred twenty-one million, one hundred thousand, forty-one".