Base | Representation |
---|---|
bin | 10000001001111110111… |
… | …000111111100101000111 |
3 | 10221010200212102120020021 |
4 | 100021332320333211013 |
5 | 121142222442311241 |
6 | 2210011031120011 |
7 | 143132354652055 |
oct | 20117670774507 |
9 | 3833625376207 |
10 | 1110230432071 |
11 | 398934154032 |
12 | 15b205b13007 |
13 | 80904446587 |
14 | 3ba420911d5 |
15 | 1dd2dbca0d1 |
hex | 1027ee3f947 |
1110230432071 has 2 divisors, whose sum is σ = 1110230432072. Its totient is φ = 1110230432070.
The previous prime is 1110230432033. The next prime is 1110230432123. The reversal of 1110230432071 is 1702340320111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1110230432071 - 213 = 1110230423879 is a prime.
It is a super-2 number, since 2×11102304320712 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1110230432471) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555115216035 + 555115216036.
It is an arithmetic number, because the mean of its divisors is an integer number (555115216036).
Almost surely, 21110230432071 is an apocalyptic number.
1110230432071 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110230432071 is an equidigital number, since it uses as much as digits as its factorization.
1110230432071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 1110230432071 its reverse (1702340320111), we get a palindrome (2812570752182).
The spelling of 1110230432071 in words is "one trillion, one hundred ten billion, two hundred thirty million, four hundred thirty-two thousand, seventy-one".
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