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111023414431 is a prime number
BaseRepresentation
bin110011101100110000…
…0101101110010011111
3101121120102010211001021
41213121200231302133
53304333443230211
6123000425025011
711010156310666
oct1473140556237
9347512124037
10111023414431
11430a2906566
1219625625167
13a614544687
1455330a7ddd
152d4bda1771
hex19d982dc9f

111023414431 has 2 divisors, whose sum is σ = 111023414432. Its totient is φ = 111023414430.

The previous prime is 111023414423. The next prime is 111023414461. The reversal of 111023414431 is 134414320111.

It is a weak prime.

It is an emirp because it is prime and its reverse (134414320111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111023414431 - 23 = 111023414423 is a prime.

It is a super-2 number, since 2×1110234144312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 111023414396 and 111023414405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111023414461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55511707215 + 55511707216.

It is an arithmetic number, because the mean of its divisors is an integer number (55511707216).

Almost surely, 2111023414431 is an apocalyptic number.

111023414431 is a deficient number, since it is larger than the sum of its proper divisors (1).

111023414431 is an equidigital number, since it uses as much as digits as its factorization.

111023414431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 111023414431 its reverse (134414320111), we get a palindrome (245437734542).

The spelling of 111023414431 in words is "one hundred eleven billion, twenty-three million, four hundred fourteen thousand, four hundred thirty-one".