Base | Representation |
---|---|
bin | 11001001111101101110011… |
… | …001001000011001110000111 |
3 | 112120010110202110001011221021 |
4 | 121033231303021003032013 |
5 | 104023113224104234343 |
6 | 1032050555250332011 |
7 | 32246506640241211 |
oct | 3117556311031607 |
9 | 476113673034837 |
10 | 111031131321223 |
11 | 32418047067533 |
12 | 105526b128a007 |
13 | 49c526312b219 |
14 | 1d5bd14b655b1 |
15 | cc82940740ed |
hex | 64fb73243387 |
111031131321223 has 2 divisors, whose sum is σ = 111031131321224. Its totient is φ = 111031131321222.
The previous prime is 111031131321191. The next prime is 111031131321247. The reversal of 111031131321223 is 322123131130111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111031131321223 - 25 = 111031131321191 is a prime.
It is a super-2 number, since 2×1110311313212232 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111031131321023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55515565660611 + 55515565660612.
It is an arithmetic number, because the mean of its divisors is an integer number (55515565660612).
Almost surely, 2111031131321223 is an apocalyptic number.
111031131321223 is a deficient number, since it is larger than the sum of its proper divisors (1).
111031131321223 is an equidigital number, since it uses as much as digits as its factorization.
111031131321223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 25.
Adding to 111031131321223 its reverse (322123131130111), we get a palindrome (433154262451334).
The spelling of 111031131321223 in words is "one hundred eleven trillion, thirty-one billion, one hundred thirty-one million, three hundred twenty-one thousand, two hundred twenty-three".
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