1110313220141 has 2 divisors, whose sum is σ = 1110313220142. Its totient is φ = 1110313220140.

The previous prime is 1110313220089. The next prime is 1110313220143. The reversal of 1110313220141 is 1410223130111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 901400235241 + 208912984900 = 949421^2 + 457070^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1110313220141 is a prime.

It is a super-3 number, since 3×1110313220141³ (a number of 37 digits) contains 333 as substring.

Together with 1110313220143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1110313220143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555156610070 + 555156610071.

It is an arithmetic number, because the mean of its divisors is an integer number (555156610071).

Almost surely, 2^{1110313220141} is an apocalyptic number.

It is an amenable number.

1110313220141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1110313220141 is an equidigital number, since it uses as much as digits as its factorization.

1110313220141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 1110313220141 its reverse (1410223130111), we get a palindrome (2520536350252).

The spelling of 1110313220141 in words is "one trillion, one hundred ten billion, three hundred thirteen million, two hundred twenty thousand, one hundred forty-one".