Base | Representation |
---|---|
bin | 1010000110010110111111… |
… | …0000101110011000000111 |
3 | 1110022120022022202121020201 |
4 | 2201211233300232120013 |
5 | 2423413220032112012 |
6 | 35341135230311331 |
7 | 2224156346264626 |
oct | 241455760563007 |
9 | 43276268677221 |
10 | 11104365504007 |
11 | 35a1375922866 |
12 | 12b4125658547 |
13 | 6271a24a9259 |
14 | 2a56502d16bd |
15 | 143cb3cb6857 |
hex | a196fc2e607 |
11104365504007 has 2 divisors, whose sum is σ = 11104365504008. Its totient is φ = 11104365504006.
The previous prime is 11104365503953. The next prime is 11104365504047. The reversal of 11104365504007 is 70040556340111.
11104365504007 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11104365504007 - 27 = 11104365503879 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11104365504047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5552182752003 + 5552182752004.
It is an arithmetic number, because the mean of its divisors is an integer number (5552182752004).
Almost surely, 211104365504007 is an apocalyptic number.
11104365504007 is a deficient number, since it is larger than the sum of its proper divisors (1).
11104365504007 is an equidigital number, since it uses as much as digits as its factorization.
11104365504007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 50400, while the sum is 37.
The spelling of 11104365504007 in words is "eleven trillion, one hundred four billion, three hundred sixty-five million, five hundred four thousand, seven".
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