11104365504047 has 2 divisors, whose sum is σ = 11104365504048. Its totient is φ = 11104365504046.

The previous prime is 11104365504007. The next prime is 11104365504079. The reversal of 11104365504047 is 74040556340111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11104365504047 - 2³⁶ = 11035646027311 is a prime.

It is a super-3 number, since 3×11104365504047³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11104365503995 and 11104365504013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11104365504007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5552182752023 + 5552182752024.

It is an arithmetic number, because the mean of its divisors is an integer number (5552182752024).

Almost surely, 2^{11104365504047} is an apocalyptic number.

11104365504047 is a deficient number, since it is larger than the sum of its proper divisors (1).

11104365504047 is an equidigital number, since it uses as much as digits as its factorization.

11104365504047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 201600, while the sum is 41.

The spelling of 11104365504047 in words is "eleven trillion, one hundred four billion, three hundred sixty-five million, five hundred four thousand, forty-seven".