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11105556061133 is a prime number
BaseRepresentation
bin1010000110011011011010…
…1110010101101111001101
31110022200101022000011121002
42201212312232111233031
52423423134322424013
635341453320150045
72224231013663642
oct241466656255715
943280338004532
1011105556061133
1135a1926969a76
1212b43b8308325
13627332045621
142a5724483dc9
15143d33589358
hexa19b6b95bcd

11105556061133 has 2 divisors, whose sum is σ = 11105556061134. Its totient is φ = 11105556061132.

The previous prime is 11105556061043. The next prime is 11105556061177. The reversal of 11105556061133 is 33116065550111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8803456911844 + 2302099149289 = 2967062^2 + 1517267^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11105556061133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11105556061933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5552778030566 + 5552778030567.

It is an arithmetic number, because the mean of its divisors is an integer number (5552778030567).

Almost surely, 211105556061133 is an apocalyptic number.

It is an amenable number.

11105556061133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11105556061133 is an equidigital number, since it uses as much as digits as its factorization.

11105556061133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 40500, while the sum is 38.

The spelling of 11105556061133 in words is "eleven trillion, one hundred five billion, five hundred fifty-six million, sixty-one thousand, one hundred thirty-three".