Search a number
-
+
1111000001141 is a prime number
BaseRepresentation
bin10000001010101100110…
…000101010101001110101
310221012200111111201112102
4100022230300222221311
5121200312000014031
62210215241431445
7143160421123502
oct20125460525165
93835614451472
101111000001141
1139919959a728
1215b39b79b585
13809c7a032a4
143bab63784a9
151dd765407cb
hex102acc2aa75

1111000001141 has 2 divisors, whose sum is σ = 1111000001142. Its totient is φ = 1111000001140.

The previous prime is 1111000001117. The next prime is 1111000001207. The reversal of 1111000001141 is 1411000001111.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1047531780100 + 63468221041 = 1023490^2 + 251929^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1111000001141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1111000001941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555500000570 + 555500000571.

It is an arithmetic number, because the mean of its divisors is an integer number (555500000571).

Almost surely, 21111000001141 is an apocalyptic number.

It is an amenable number.

1111000001141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111000001141 is an equidigital number, since it uses as much as digits as its factorization.

1111000001141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4, while the sum is 11.

Adding to 1111000001141 its reverse (1411000001111), we get a palindrome (2522000002252).

The spelling of 1111000001141 in words is "one trillion, one hundred eleven billion, one thousand, one hundred forty-one".