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11110011101131 is a prime number
BaseRepresentation
bin1010000110101100000001…
…0000111101111111001011
31110100002212202221122120111
42201223000100331333023
52424011300320214011
635343511343135151
72224446301130515
oct241530020757713
943302782848514
1011110011101131
1135a38026a1508
1212b52402a44b7
13627892009a77
142a5a28008bb5
15143ee4746121
hexa1ac043dfcb

11110011101131 has 2 divisors, whose sum is σ = 11110011101132. Its totient is φ = 11110011101130.

The previous prime is 11110011101083. The next prime is 11110011101207. The reversal of 11110011101131 is 13110111001111.

It is a happy number.

11110011101131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (13110111001111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11110011101131 - 219 = 11110010576843 is a prime.

It is a super-2 number, since 2×111100111011312 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11110011101831) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555005550565 + 5555005550566.

It is an arithmetic number, because the mean of its divisors is an integer number (5555005550566).

Almost surely, 211110011101131 is an apocalyptic number.

11110011101131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11110011101131 is an equidigital number, since it uses as much as digits as its factorization.

11110011101131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 13.

Adding to 11110011101131 its reverse (13110111001111), we get a palindrome (24220122102242).

The spelling of 11110011101131 in words is "eleven trillion, one hundred ten billion, eleven million, one hundred one thousand, one hundred thirty-one".