11110011101083 has 2 divisors, whose sum is σ = 11110011101084. Its totient is φ = 11110011101082.

The previous prime is 11110011101081. The next prime is 11110011101131. The reversal of 11110011101083 is 38010111001111.

11110011101083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (38010111001111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11110011101083 - 2¹ = 11110011101081 is a prime.

Together with 11110011101081, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 11110011101083.

It is not a weakly prime, because it can be changed into another prime (11110011101081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555005550541 + 5555005550542.

It is an arithmetic number, because the mean of its divisors is an integer number (5555005550542).

Almost surely, 2^{11110011101083} is an apocalyptic number.

11110011101083 is a deficient number, since it is larger than the sum of its proper divisors (1).

11110011101083 is an equidigital number, since it uses as much as digits as its factorization.

11110011101083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 19.

Adding to 11110011101083 its reverse (38010111001111), we get a palindrome (49120122102194).

The spelling of 11110011101083 in words is "eleven trillion, one hundred ten billion, eleven million, one hundred one thousand, eighty-three".