111100121102141 has 2 divisors, whose sum is σ = 111100121102142. Its totient is φ = 111100121102140.

The previous prime is 111100121102101. The next prime is 111100121102143. The reversal of 111100121102141 is 141201121001111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 76136008104025 + 34964112998116 = 8725595^2 + 5913046^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-111100121102141 is a prime.

Together with 111100121102143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111100121102143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55550060551070 + 55550060551071.

It is an arithmetic number, because the mean of its divisors is an integer number (55550060551071).

Almost surely, 2^{111100121102141} is an apocalyptic number.

It is an amenable number.

111100121102141 is a deficient number, since it is larger than the sum of its proper divisors (1).

111100121102141 is an equidigital number, since it uses as much as digits as its factorization.

111100121102141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16, while the sum is 17.

Adding to 111100121102141 its reverse (141201121001111), we get a palindrome (252301242103252).

The spelling of 111100121102141 in words is "one hundred eleven trillion, one hundred billion, one hundred twenty-one million, one hundred two thousand, one hundred forty-one".