Base | Representation |
---|---|
bin | 10100101100011010… |
… | …10111010010011101 |
3 | 1001200021110111122121 |
4 | 22112031113102131 |
5 | 140223131122003 |
6 | 5034234142541 |
7 | 542213420413 |
oct | 122615272235 |
9 | 31607414577 |
10 | 11110020253 |
11 | 4791353722 |
12 | 21a0881a51 |
13 | 1080968ca7 |
14 | 77574d2b3 |
15 | 450572cbd |
hex | 29635749d |
11110020253 has 2 divisors, whose sum is σ = 11110020254. Its totient is φ = 11110020252.
The previous prime is 11110020241. The next prime is 11110020269. The reversal of 11110020253 is 35202001111.
It is an a-pointer prime, because the next prime (11110020269) can be obtained adding 11110020253 to its sum of digits (16).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9150452964 + 1959567289 = 95658^2 + 44267^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11110020253 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11110020283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555010126 + 5555010127.
It is an arithmetic number, because the mean of its divisors is an integer number (5555010127).
Almost surely, 211110020253 is an apocalyptic number.
It is an amenable number.
11110020253 is a deficient number, since it is larger than the sum of its proper divisors (1).
11110020253 is an equidigital number, since it uses as much as digits as its factorization.
11110020253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60, while the sum is 16.
Adding to 11110020253 its reverse (35202001111), we get a palindrome (46312021364).
The spelling of 11110020253 in words is "eleven billion, one hundred ten million, twenty thousand, two hundred fifty-three".
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