11110043741 has 2 divisors, whose sum is σ = 11110043742. Its totient is φ = 11110043740.

The previous prime is 11110043683. The next prime is 11110043743. The reversal of 11110043741 is 14734001111.

11110043741 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9107839225 + 2002204516 = 95435^2 + 44746^2 .

It is an emirp because it is prime and its reverse (14734001111) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11110043741 is a prime.

Together with 11110043743, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11110043743) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555021870 + 5555021871.

It is an arithmetic number, because the mean of its divisors is an integer number (5555021871).

Almost surely, 2^11110043741 is an apocalyptic number.

It is an amenable number.

11110043741 is a deficient number, since it is larger than the sum of its proper divisors (1).

11110043741 is an equidigital number, since it uses as much as digits as its factorization.

11110043741 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 336, while the sum is 23.

Adding to 11110043741 its reverse (14734001111), we get a palindrome (25844044852).

The spelling of 11110043741 in words is "eleven billion, one hundred ten million, forty-three thousand, seven hundred forty-one".