Base | Representation |
---|---|
bin | 110011101111001000… |
… | …0110011110111101111 |
3 | 101121202222010211210012 |
4 | 1213132100303313233 |
5 | 3310014400143434 |
6 | 123012353403435 |
7 | 11012145014111 |
oct | 1473620636757 |
9 | 347688124705 |
10 | 111103131119 |
11 | 43133903922 |
12 | 1964826957b |
13 | a627c05b06 |
14 | 553d8d93b1 |
15 | 2d53d9b3ce |
hex | 19de433def |
111103131119 has 2 divisors, whose sum is σ = 111103131120. Its totient is φ = 111103131118.
The previous prime is 111103131107. The next prime is 111103131133. The reversal of 111103131119 is 911131301111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 111103131119 - 232 = 106808163823 is a prime.
It is a super-2 number, since 2×1111031311192 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 111103131094 and 111103131103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111103131149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55551565559 + 55551565560.
It is an arithmetic number, because the mean of its divisors is an integer number (55551565560).
Almost surely, 2111103131119 is an apocalyptic number.
111103131119 is a deficient number, since it is larger than the sum of its proper divisors (1).
111103131119 is an equidigital number, since it uses as much as digits as its factorization.
111103131119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 23.
The spelling of 111103131119 in words is "one hundred eleven billion, one hundred three million, one hundred thirty-one thousand, one hundred nineteen".
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