Base | Representation |
---|---|
bin | 110011101111001000… |
… | …0110011110111111101 |
3 | 101121202222010211210201 |
4 | 1213132100303313331 |
5 | 3310014400144013 |
6 | 123012353403501 |
7 | 11012145014131 |
oct | 1473620636775 |
9 | 347688124721 |
10 | 111103131133 |
11 | 43133903935 |
12 | 19648269591 |
13 | a627c05b17 |
14 | 553d8d93c1 |
15 | 2d53d9b3dd |
hex | 19de433dfd |
111103131133 has 2 divisors, whose sum is σ = 111103131134. Its totient is φ = 111103131132.
The previous prime is 111103131119. The next prime is 111103131149. The reversal of 111103131133 is 331131301111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 109622574649 + 1480556484 = 331093^2 + 38478^2 .
It is a cyclic number.
It is not a de Polignac number, because 111103131133 - 213 = 111103122941 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 111103131133.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111103131233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55551565566 + 55551565567.
It is an arithmetic number, because the mean of its divisors is an integer number (55551565567).
Almost surely, 2111103131133 is an apocalyptic number.
It is an amenable number.
111103131133 is a deficient number, since it is larger than the sum of its proper divisors (1).
111103131133 is an equidigital number, since it uses as much as digits as its factorization.
111103131133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 19.
Adding to 111103131133 its reverse (331131301111), we get a palindrome (442234432244).
The spelling of 111103131133 in words is "one hundred eleven billion, one hundred three million, one hundred thirty-one thousand, one hundred thirty-three".
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