Base | Representation |
---|---|
bin | 10000001010101110110… |
… | …010011101000111101111 |
3 | 10221012202212112021201021 |
4 | 100022232302131013233 |
5 | 121200344202240211 |
6 | 2210222454555011 |
7 | 143161313246662 |
oct | 20125662350757 |
9 | 3835685467637 |
10 | 1111034024431 |
11 | 399206818951 |
12 | 15b3ab068a67 |
13 | 80a01a86606 |
14 | 3babaab36d9 |
15 | 1dd79511771 |
hex | 102aec9d1ef |
1111034024431 has 2 divisors, whose sum is σ = 1111034024432. Its totient is φ = 1111034024430.
The previous prime is 1111034024369. The next prime is 1111034024447. The reversal of 1111034024431 is 1344204301111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1111034024431 - 233 = 1102444089839 is a prime.
It is a super-2 number, since 2×11110340244312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1111034024396 and 1111034024405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1111034024131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555517012215 + 555517012216.
It is an arithmetic number, because the mean of its divisors is an integer number (555517012216).
Almost surely, 21111034024431 is an apocalyptic number.
1111034024431 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111034024431 is an equidigital number, since it uses as much as digits as its factorization.
1111034024431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1111034024431 its reverse (1344204301111), we get a palindrome (2455238325542).
The spelling of 1111034024431 in words is "one trillion, one hundred eleven billion, thirty-four million, twenty-four thousand, four hundred thirty-one".
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