Base | Representation |
---|---|
bin | 110011101111010101… |
… | …1000000010111100101 |
3 | 101121210110001201110002 |
4 | 1213132223000113211 |
5 | 3310023124414203 |
6 | 123013200511045 |
7 | 11012260254245 |
oct | 1473653002745 |
9 | 347713051402 |
10 | 111109998053 |
11 | 4313777407a |
12 | 1964a61b485 |
13 | a62946b5a2 |
14 | 55407a5b25 |
15 | 2d547a5d88 |
hex | 19deac05e5 |
111109998053 has 2 divisors, whose sum is σ = 111109998054. Its totient is φ = 111109998052.
The previous prime is 111109998031. The next prime is 111109998059. The reversal of 111109998053 is 350899901111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 108703408804 + 2406589249 = 329702^2 + 49057^2 .
It is a cyclic number.
It is not a de Polignac number, because 111109998053 - 220 = 111108949477 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 111109997989 and 111109998007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111109998059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55554999026 + 55554999027.
It is an arithmetic number, because the mean of its divisors is an integer number (55554999027).
Almost surely, 2111109998053 is an apocalyptic number.
It is an amenable number.
111109998053 is a deficient number, since it is larger than the sum of its proper divisors (1).
111109998053 is an equidigital number, since it uses as much as digits as its factorization.
111109998053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 87480, while the sum is 47.
The spelling of 111109998053 in words is "one hundred eleven billion, one hundred nine million, nine hundred ninety-eight thousand, fifty-three".
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