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111111099917 is a prime number
BaseRepresentation
bin110011101111010111…
…1001101011000001101
3101121210112010200220212
41213132233031120031
53310023420144132
6123013240252205
711012302523546
oct1473657153015
9347715120825
10111111099917
1143138356a04
121964aa71065
13a629765c8c
1455409b14cd
152d549225b2
hex19debcd60d

111111099917 has 2 divisors, whose sum is σ = 111111099918. Its totient is φ = 111111099916.

The previous prime is 111111099871. The next prime is 111111099919. The reversal of 111111099917 is 719990111111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108640115236 + 2470984681 = 329606^2 + 49709^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-111111099917 is a prime.

Together with 111111099919, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111111099919) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55555549958 + 55555549959.

It is an arithmetic number, because the mean of its divisors is an integer number (55555549959).

Almost surely, 2111111099917 is an apocalyptic number.

It is an amenable number.

111111099917 is a deficient number, since it is larger than the sum of its proper divisors (1).

111111099917 is an equidigital number, since it uses as much as digits as its factorization.

111111099917 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5103, while the sum is 41.

The spelling of 111111099917 in words is "one hundred eleven billion, one hundred eleven million, ninety-nine thousand, nine hundred seventeen".