111111111210013 has 2 divisors, whose sum is σ = 111111111210014. Its totient is φ = 111111111210012.

The previous prime is 111111111210007. The next prime is 111111111210019. The reversal of 111111111210013 is 310012111111111.

It is a balanced prime because it is at equal distance from previous prime (111111111210007) and next prime (111111111210019).

It can be written as a sum of positive squares in only one way, i.e., 90131440962564 + 20979670247449 = 9493758^2 + 4580357^2 .

It is an emirp because it is prime and its reverse (310012111111111) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-111111111210013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111111111210019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55555555605006 + 55555555605007.

It is an arithmetic number, because the mean of its divisors is an integer number (55555555605007).

Almost surely, 2^{111111111210013} is an apocalyptic number.

It is an amenable number.

111111111210013 is a deficient number, since it is larger than the sum of its proper divisors (1).

111111111210013 is an equidigital number, since it uses as much as digits as its factorization.

111111111210013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 16.

Adding to 111111111210013 its reverse (310012111111111), we get a palindrome (421123222321124).

The spelling of 111111111210013 in words is "one hundred eleven trillion, one hundred eleven billion, one hundred eleven million, two hundred ten thousand, thirteen".