Base | Representation |
---|---|
bin | 110011101111011001… |
… | …0101001011001000101 |
3 | 101121210120211111002202 |
4 | 1213132302221121011 |
5 | 3310024133013333 |
6 | 123013311444245 |
7 | 11012313266102 |
oct | 1473662513105 |
9 | 347716744082 |
10 | 111112001093 |
11 | 43138911a85 |
12 | 1964b226685 |
13 | a6299c0212 |
14 | 5540b67aa9 |
15 | 2d54a4e5e8 |
hex | 19deca9645 |
111112001093 has 2 divisors, whose sum is σ = 111112001094. Its totient is φ = 111112001092.
The previous prime is 111112001089. The next prime is 111112001101. The reversal of 111112001093 is 390100211111.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 63858806209 + 47253194884 = 252703^2 + 217378^2 .
It is a cyclic number.
It is not a de Polignac number, because 111112001093 - 22 = 111112001089 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111112001023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55556000546 + 55556000547.
It is an arithmetic number, because the mean of its divisors is an integer number (55556000547).
Almost surely, 2111112001093 is an apocalyptic number.
It is an amenable number.
111112001093 is a deficient number, since it is larger than the sum of its proper divisors (1).
111112001093 is an equidigital number, since it uses as much as digits as its factorization.
111112001093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 20.
The spelling of 111112001093 in words is "one hundred eleven billion, one hundred twelve million, one thousand, ninety-three".
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