Base | Representation |
---|---|
bin | 110011101111011011… |
… | …0111011010111010001 |
3 | 101121210122221111110021 |
4 | 1213132312323113101 |
5 | 3310024424421111 |
6 | 123013351503441 |
7 | 11012325651556 |
oct | 1473666732721 |
9 | 347718844407 |
10 | 111113123281 |
11 | 43139509106 |
12 | 1964b687b81 |
13 | a629cc3c34 |
14 | 5540d7aa2d |
15 | 2d54bc1d71 |
hex | 19dedbb5d1 |
111113123281 has 2 divisors, whose sum is σ = 111113123282. Its totient is φ = 111113123280.
The previous prime is 111113123273. The next prime is 111113123327. The reversal of 111113123281 is 182321311111.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 110833063056 + 280060225 = 332916^2 + 16735^2 .
It is a cyclic number.
It is not a de Polignac number, because 111113123281 - 23 = 111113123273 is a prime.
It is a super-2 number, since 2×1111131232812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (111113123221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55556561640 + 55556561641.
It is an arithmetic number, because the mean of its divisors is an integer number (55556561641).
Almost surely, 2111113123281 is an apocalyptic number.
It is an amenable number.
111113123281 is a deficient number, since it is larger than the sum of its proper divisors (1).
111113123281 is an equidigital number, since it uses as much as digits as its factorization.
111113123281 is an evil number, because the sum of its binary digits is even.
The product of its digits is 288, while the sum is 25.
Adding to 111113123281 its reverse (182321311111), we get a palindrome (293434434392).
The spelling of 111113123281 in words is "one hundred eleven billion, one hundred thirteen million, one hundred twenty-three thousand, two hundred eighty-one".
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