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111113131309 is a prime number
BaseRepresentation
bin110011101111011011…
…0111101010100101101
3101121210122221220110121
41213132312331110231
53310024430200214
6123013352004541
711012326014145
oct1473666752455
9347718856417
10111113131309
1143139514144
121964b690751
13a629cc779b
145540d7d925
152d54bc4424
hex19dedbd52d

111113131309 has 2 divisors, whose sum is σ = 111113131310. Its totient is φ = 111113131308.

The previous prime is 111113131289. The next prime is 111113131387. The reversal of 111113131309 is 903131311111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 103201562500 + 7911568809 = 321250^2 + 88947^2 .

It is a cyclic number.

It is not a de Polignac number, because 111113131309 - 217 = 111113000237 is a prime.

It is a super-2 number, since 2×1111131313092 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111113131009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55556565654 + 55556565655.

It is an arithmetic number, because the mean of its divisors is an integer number (55556565655).

Almost surely, 2111113131309 is an apocalyptic number.

It is an amenable number.

111113131309 is a deficient number, since it is larger than the sum of its proper divisors (1).

111113131309 is an equidigital number, since it uses as much as digits as its factorization.

111113131309 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 243, while the sum is 25.

The spelling of 111113131309 in words is "one hundred eleven billion, one hundred thirteen million, one hundred thirty-one thousand, three hundred nine".