Base | Representation |
---|---|
bin | 1010000110110000111011… |
… | …1111111000010010100101 |
3 | 1110100020021211111100112220 |
4 | 2201230032333320102211 |
5 | 2424022001444141123 |
6 | 35344250411102553 |
7 | 2224524110562201 |
oct | 241541677702245 |
9 | 43306254440486 |
10 | 11111332021413 |
11 | 35a4320288468 |
12 | 12b554a741a59 |
13 | 627a4288acc0 |
14 | 2a5b11613b01 |
15 | 1440706b9ce3 |
hex | a1b0eff84a5 |
11111332021413 has 64 divisors (see below), whose sum is σ = 16671229182720. Its totient is φ = 6537594488832.
The previous prime is 11111332021333. The next prime is 11111332021429. The reversal of 11111332021413 is 31412023311111.
It is not a de Polignac number, because 11111332021413 - 210 = 11111332020389 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11111332021453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 39402031 + ... + 39683027.
It is an arithmetic number, because the mean of its divisors is an integer number (260487955980).
Almost surely, 211111332021413 is an apocalyptic number.
11111332021413 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
11111332021413 is a deficient number, since it is larger than the sum of its proper divisors (5559897161307).
11111332021413 is a wasteful number, since it uses less digits than its factorization.
11111332021413 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 281526.
The product of its (nonzero) digits is 432, while the sum is 24.
Adding to 11111332021413 its reverse (31412023311111), we get a palindrome (42523355332524).
The spelling of 11111332021413 in words is "eleven trillion, one hundred eleven billion, three hundred thirty-two million, twenty-one thousand, four hundred thirteen".
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