Base | Representation |
---|---|
bin | 1010000110110001000101… |
… | …0001101101011100110111 |
3 | 1110100020101111102120100221 |
4 | 2201230101101231130313 |
5 | 2424022041241000124 |
6 | 35344254254315211 |
7 | 2224525053532003 |
oct | 241542121553467 |
9 | 43306344376327 |
10 | 11111370250039 |
11 | 35a433a919174 |
12 | 12b555b4b8b07 |
13 | 627a4a7844a7 |
14 | 2a5b16725703 |
15 | 144073c1bce4 |
hex | a1b1146d737 |
11111370250039 has 2 divisors, whose sum is σ = 11111370250040. Its totient is φ = 11111370250038.
The previous prime is 11111370249989. The next prime is 11111370250061. The reversal of 11111370250039 is 93005207311111.
11111370250039 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11111370250039 - 213 = 11111370241847 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11111370249986 and 11111370250013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11111370250069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555685125019 + 5555685125020.
It is an arithmetic number, because the mean of its divisors is an integer number (5555685125020).
Almost surely, 211111370250039 is an apocalyptic number.
11111370250039 is a deficient number, since it is larger than the sum of its proper divisors (1).
11111370250039 is an equidigital number, since it uses as much as digits as its factorization.
11111370250039 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5670, while the sum is 34.
The spelling of 11111370250039 in words is "eleven trillion, one hundred eleven billion, three hundred seventy million, two hundred fifty thousand, thirty-nine".
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