Base | Representation |
---|---|
bin | 1010000110110011011110… |
… | …0010100110011011111111 |
3 | 1110100022001020101121120122 |
4 | 2201230313202212123333 |
5 | 2424024400111240332 |
6 | 35344442110005155 |
7 | 2224550010240062 |
oct | 241546742463377 |
9 | 43308036347518 |
10 | 11112012211967 |
11 | 35a463a227717 |
12 | 12b56ba4a67bb |
13 | 627b20782914 |
14 | 2a5b77ab28d9 |
15 | 1440b0277c12 |
hex | a1b378a66ff |
11112012211967 has 2 divisors, whose sum is σ = 11112012211968. Its totient is φ = 11112012211966.
The previous prime is 11112012211957. The next prime is 11112012212123. The reversal of 11112012211967 is 76911221021111.
It is a weak prime.
It is an emirp because it is prime and its reverse (76911221021111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11112012211967 - 26 = 11112012211903 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11112012211957) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556006105983 + 5556006105984.
It is an arithmetic number, because the mean of its divisors is an integer number (5556006105984).
Almost surely, 211112012211967 is an apocalyptic number.
11112012211967 is a deficient number, since it is larger than the sum of its proper divisors (1).
11112012211967 is an equidigital number, since it uses as much as digits as its factorization.
11112012211967 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 35.
The spelling of 11112012211967 in words is "eleven trillion, one hundred twelve billion, twelve million, two hundred eleven thousand, nine hundred sixty-seven".
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