Base | Representation |
---|---|
bin | 1010000110110011011110… |
… | …0010100110011110011011 |
3 | 1110100022001020101121210102 |
4 | 2201230313202212132123 |
5 | 2424024400111241443 |
6 | 35344442110010015 |
7 | 2224550010240404 |
oct | 241546742463633 |
9 | 43308036347712 |
10 | 11112012212123 |
11 | 35a463a227849 |
12 | 12b56ba4a690b |
13 | 627b20782a04 |
14 | 2a5b77ab29ab |
15 | 1440b0277cb8 |
hex | a1b378a679b |
11112012212123 has 2 divisors, whose sum is σ = 11112012212124. Its totient is φ = 11112012212122.
The previous prime is 11112012211967. The next prime is 11112012212201. The reversal of 11112012212123 is 32121221021111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11112012212123 - 222 = 11112008017819 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11112012212095 and 11112012212104.
It is not a weakly prime, because it can be changed into another prime (11112012218123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556006106061 + 5556006106062.
It is an arithmetic number, because the mean of its divisors is an integer number (5556006106062).
Almost surely, 211112012212123 is an apocalyptic number.
11112012212123 is a deficient number, since it is larger than the sum of its proper divisors (1).
11112012212123 is an equidigital number, since it uses as much as digits as its factorization.
11112012212123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 20.
Adding to 11112012212123 its reverse (32121221021111), we get a palindrome (43233233233234).
The spelling of 11112012212123 in words is "eleven trillion, one hundred twelve billion, twelve million, two hundred twelve thousand, one hundred twenty-three".
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