Search a number
-
+
1111213000127 is a prime number
BaseRepresentation
bin10000001010111001011…
…101001100010110111111
310221020020100022012012202
4100022321131030112333
5121201231012001002
62210252331022115
7143165615441006
oct20127135142677
93836210265182
101111213000127
11399298850a4a
1215b43ab9a93b
1380a2cb8c1a9
143bad6781c3d
151dd8a0b6502
hex102b974c5bf

1111213000127 has 2 divisors, whose sum is σ = 1111213000128. Its totient is φ = 1111213000126.

The previous prime is 1111213000091. The next prime is 1111213000159. The reversal of 1111213000127 is 7210003121111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1111213000127 - 212 = 1111212996031 is a prime.

It is a super-2 number, since 2×11112130001272 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1111213000099 and 1111213000108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1111213080127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555606500063 + 555606500064.

It is an arithmetic number, because the mean of its divisors is an integer number (555606500064).

Almost surely, 21111213000127 is an apocalyptic number.

1111213000127 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111213000127 is an equidigital number, since it uses as much as digits as its factorization.

1111213000127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 84, while the sum is 20.

Adding to 1111213000127 its reverse (7210003121111), we get a palindrome (8321216121238).

The spelling of 1111213000127 in words is "one trillion, one hundred eleven billion, two hundred thirteen million, one hundred twenty-seven", and thus it is an aban number.