Base | Representation |
---|---|
bin | 10000001010111001011… |
… | …101001100010111011111 |
3 | 10221020020100022012020221 |
4 | 100022321131030113133 |
5 | 121201231012001114 |
6 | 2210252331022211 |
7 | 143165615441053 |
oct | 20127135142737 |
9 | 3836210265227 |
10 | 1111213000159 |
11 | 399298850a79 |
12 | 15b43ab9a967 |
13 | 80a2cb8c202 |
14 | 3bad6781c63 |
15 | 1dd8a0b6524 |
hex | 102b974c5df |
1111213000159 has 2 divisors, whose sum is σ = 1111213000160. Its totient is φ = 1111213000158.
The previous prime is 1111213000127. The next prime is 1111213000207. The reversal of 1111213000159 is 9510003121111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1111213000159 - 25 = 1111213000127 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1111213090159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555606500079 + 555606500080.
It is an arithmetic number, because the mean of its divisors is an integer number (555606500080).
Almost surely, 21111213000159 is an apocalyptic number.
1111213000159 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111213000159 is an equidigital number, since it uses as much as digits as its factorization.
1111213000159 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 270, while the sum is 25.
The spelling of 1111213000159 in words is "one trillion, one hundred eleven billion, two hundred thirteen million, one hundred fifty-nine", and thus it is an aban number.
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