1111220000047 has 2 divisors, whose sum is σ = 1111220000048. Its totient is φ = 1111220000046.

The previous prime is 1111219999987. The next prime is 1111220000053. The reversal of 1111220000047 is 7400000221111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1111220000047 - 2³⁵ = 1076860261679 is a prime.

It is a super-3 number, since 3×1111220000047³ (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1111219999979 and 1111220000033.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1111220000087) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555610000023 + 555610000024.

It is an arithmetic number, because the mean of its divisors is an integer number (555610000024).

Almost surely, 2^{1111220000047} is an apocalyptic number.

1111220000047 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111220000047 is an equidigital number, since it uses as much as digits as its factorization.

1111220000047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 112, while the sum is 19.

Adding to 1111220000047 its reverse (7400000221111), we get a palindrome (8511220221158).

The spelling of 1111220000047 in words is "one trillion, one hundred eleven billion, two hundred twenty million, forty-seven", and thus it is an aban number.