Search a number
-
+
111122020121112 = 2333711134611114837
BaseRepresentation
bin11001010001000010011100…
…100010010011101000011000
3112120110011100122100121022000
4121101002130202103220120
5104031110344122333422
61032200430141001000
732256205151265120
oct3121023442235030
9476404318317260
10111122020121112
1132452647460090
1210568237853160
134a009b9124ca0
141d62497b05c80
15cca813468cac
hex65109c893a18

111122020121112 has 512 divisors, whose sum is σ = 415340477798400. Its totient is φ = 26584825190400.

The previous prime is 111122020121089. The next prime is 111122020121153. The reversal of 111122020121112 is 211121020221111.

It is a happy number.

111122020121112 is a `hidden beast` number, since 1 + 111 + 220 + 201 + 21 + 112 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 99118158 + ... + 100232994.

It is an arithmetic number, because the mean of its divisors is an integer number (811211870700).

Almost surely, 2111122020121112 is an apocalyptic number.

111122020121112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 111122020121112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (207670238899200).

111122020121112 is an abundant number, since it is smaller than the sum of its proper divisors (304218457677288).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

111122020121112 is a wasteful number, since it uses less digits than its factorization.

111122020121112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1115344 (or 1115334 counting only the distinct ones).

The product of its (nonzero) digits is 32, while the sum is 18.

Adding to 111122020121112 its reverse (211121020221111), we get a palindrome (322243040342223).

Subtracting 111122020121112 from its reverse (211121020221111), we obtain a palindrome (99999000099999).

The spelling of 111122020121112 in words is "one hundred eleven trillion, one hundred twenty-two billion, twenty million, one hundred twenty-one thousand, one hundred twelve".