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111122097816797 is a prime number
BaseRepresentation
bin11001010001000010100001…
…001010101100010011011101
3112120110011120001112221201222
4121101002201022230103131
5104031111024020114142
61032200441554143125
732256210113553134
oct3121024112542335
9476404501487658
10111122097816797
11324526872a7aa1
1210568259881aa5
134a009cc259572
141d624a416c91b
15cca81a1b4bd2
hex6510a12ac4dd

111122097816797 has 2 divisors, whose sum is σ = 111122097816798. Its totient is φ = 111122097816796.

The previous prime is 111122097816787. The next prime is 111122097816799. The reversal of 111122097816797 is 797618790221111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 71199489604441 + 39922608212356 = 8437979^2 + 6318434^2 .

It is a cyclic number.

It is not a de Polignac number, because 111122097816797 - 212 = 111122097812701 is a prime.

Together with 111122097816799, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111122097816799) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55561048908398 + 55561048908399.

It is an arithmetic number, because the mean of its divisors is an integer number (55561048908399).

Almost surely, 2111122097816797 is an apocalyptic number.

It is an amenable number.

111122097816797 is a deficient number, since it is larger than the sum of its proper divisors (1).

111122097816797 is an equidigital number, since it uses as much as digits as its factorization.

111122097816797 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5334336, while the sum is 62.

The spelling of 111122097816797 in words is "one hundred eleven trillion, one hundred twenty-two billion, ninety-seven million, eight hundred sixteen thousand, seven hundred ninety-seven".