Base | Representation |
---|---|
bin | 11001010001000010100010… |
… | …100000000111011010111111 |
3 | 112120110011121121200122120222 |
4 | 121101002202200013122333 |
5 | 104031111100233210421 |
6 | 1032200444114131555 |
7 | 32256210505110563 |
oct | 3121024240073277 |
9 | 476404547618528 |
10 | 111122120210111 |
11 | 32452698a0246a |
12 | 10568265280bbb |
13 | 4a00a03a9a14a |
14 | 1d624a711b6a3 |
15 | cca81c139cab |
hex | 6510a28076bf |
111122120210111 has 2 divisors, whose sum is σ = 111122120210112. Its totient is φ = 111122120210110.
The previous prime is 111122120210053. The next prime is 111122120210113. The reversal of 111122120210111 is 111012021221111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111122120210111 is a prime.
Together with 111122120210113, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 111122120210111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111122120210113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55561060105055 + 55561060105056.
It is an arithmetic number, because the mean of its divisors is an integer number (55561060105056).
Almost surely, 2111122120210111 is an apocalyptic number.
111122120210111 is a deficient number, since it is larger than the sum of its proper divisors (1).
111122120210111 is an equidigital number, since it uses as much as digits as its factorization.
111122120210111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16, while the sum is 17.
Adding to 111122120210111 its reverse (111012021221111), we get a palindrome (222134141431222).
The spelling of 111122120210111 in words is "one hundred eleven trillion, one hundred twenty-two billion, one hundred twenty million, two hundred ten thousand, one hundred eleven".
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