Base | Representation |
---|---|
bin | 10000001010111010000… |
… | …101000101010000100111 |
3 | 10221020021001222110002012 |
4 | 100022322011011100213 |
5 | 121201241201104212 |
6 | 2210253343104435 |
7 | 143166103351652 |
oct | 20127205052047 |
9 | 3836231873065 |
10 | 1111223456807 |
11 | 3992a3743232 |
12 | 15b4425a211b |
13 | 80a320b0889 |
14 | 3bad7d04899 |
15 | 1dd8ae7e922 |
hex | 102ba145427 |
1111223456807 has 2 divisors, whose sum is σ = 1111223456808. Its totient is φ = 1111223456806.
The previous prime is 1111223456771. The next prime is 1111223456809. The reversal of 1111223456807 is 7086543221111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1111223456807 is a prime.
Together with 1111223456809, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1111223456809) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555611728403 + 555611728404.
It is an arithmetic number, because the mean of its divisors is an integer number (555611728404).
Almost surely, 21111223456807 is an apocalyptic number.
1111223456807 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111223456807 is an equidigital number, since it uses as much as digits as its factorization.
1111223456807 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80640, while the sum is 41.
Adding to 1111223456807 its reverse (7086543221111), we get a palindrome (8197766677918).
The spelling of 1111223456807 in words is "one trillion, one hundred eleven billion, two hundred twenty-three million, four hundred fifty-six thousand, eight hundred seven".
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