Base | Representation |
---|---|
bin | 10100101100101100… |
… | …11100100011111011 |
3 | 1001200102221110121212 |
4 | 22112112130203323 |
5 | 140224233314042 |
6 | 5034401153335 |
7 | 542242564661 |
oct | 122626344373 |
9 | 31612843555 |
10 | 11112401147 |
11 | 479272a501 |
12 | 21a162b84b |
13 | 10812c08c3 |
14 | 775bacc31 |
15 | 450893482 |
hex | 29659c8fb |
11112401147 has 2 divisors, whose sum is σ = 11112401148. Its totient is φ = 11112401146.
The previous prime is 11112401141. The next prime is 11112401173. The reversal of 11112401147 is 74110421111.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11112401147 is a prime.
It is not a weakly prime, because it can be changed into another prime (11112401141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556200573 + 5556200574.
It is an arithmetic number, because the mean of its divisors is an integer number (5556200574).
Almost surely, 211112401147 is an apocalyptic number.
11112401147 is a deficient number, since it is larger than the sum of its proper divisors (1).
11112401147 is an equidigital number, since it uses as much as digits as its factorization.
11112401147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 224, while the sum is 23.
Adding to 11112401147 its reverse (74110421111), we get a palindrome (85222822258).
The spelling of 11112401147 in words is "eleven billion, one hundred twelve million, four hundred one thousand, one hundred forty-seven".
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