11112503300050 has 24 divisors (see below), whose sum is σ = 20777472156672. Its totient is φ = 4421729058000.

The previous prime is 11112503300047. The next prime is 11112503300057. The reversal of 11112503300050 is 5000330521111.

It is a junction number, because it is equal to n+sod(n) for n = 11112503299994 and 11112503300030.

It is not an unprimeable number, because it can be changed into a prime (11112503300057) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 581796906 + ... + 581816005.

It is an arithmetic number, because the mean of its divisors is an integer number (865728006528).

Almost surely, 2^{11112503300050} is an apocalyptic number.

11112503300050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11112503300050 is a deficient number, since it is larger than the sum of its proper divisors (9664968856622).

11112503300050 is a wasteful number, since it uses less digits than its factorization.

11112503300050 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1163613114 (or 1163613109 counting only the distinct ones).

The product of its (nonzero) digits is 450, while the sum is 22.

Adding to 11112503300050 its reverse (5000330521111), we get a palindrome (16112833821161).

The spelling of 11112503300050 in words is "eleven trillion, one hundred twelve billion, five hundred three million, three hundred thousand, fifty".