1111300114032 has 60 divisors (see below), whose sum is σ = 3123797805960. Its totient is φ = 368801495424.

The previous prime is 1111300114007. The next prime is 1111300114037. The reversal of 1111300114032 is 2304110031111.

It is a happy number.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 1111300113996 and 1111300114014.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1111300114037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 16965907 + ... + 17031282.

It is an arithmetic number, because the mean of its divisors is an integer number (52063296766).

Almost surely, 2^{1111300114032} is an apocalyptic number.

1111300114032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1111300114032 is an abundant number, since it is smaller than the sum of its proper divisors (2012497691928).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1111300114032 is a wasteful number, since it uses less digits than its factorization.

1111300114032 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33997430 (or 33997421 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 1111300114032 its reverse (2304110031111), we get a palindrome (3415410145143).

The spelling of 1111300114032 in words is "one trillion, one hundred eleven billion, three hundred million, one hundred fourteen thousand, thirty-two".