Base | Representation |
---|---|
bin | 110011110000000000… |
… | …0001010111001100111 |
3 | 101121212000001222002221 |
4 | 1213200000022321213 |
5 | 3310044333322211 |
6 | 123015315213211 |
7 | 11012651106643 |
oct | 1474000127147 |
9 | 347760058087 |
10 | 111132323431 |
11 | 431493324a8 |
12 | 19655ba7207 |
13 | a630c8727c |
14 | 5543737c23 |
15 | 2d56715c71 |
hex | 19e000ae67 |
111132323431 has 2 divisors, whose sum is σ = 111132323432. Its totient is φ = 111132323430.
The previous prime is 111132323413. The next prime is 111132323441. The reversal of 111132323431 is 134323231111.
Together with previous prime (111132323413) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111132323431 - 29 = 111132322919 is a prime.
It is a super-2 number, since 2×1111323234312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 111132323396 and 111132323405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111132323441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55566161715 + 55566161716.
It is an arithmetic number, because the mean of its divisors is an integer number (55566161716).
Almost surely, 2111132323431 is an apocalyptic number.
111132323431 is a deficient number, since it is larger than the sum of its proper divisors (1).
111132323431 is an equidigital number, since it uses as much as digits as its factorization.
111132323431 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1296, while the sum is 25.
Adding to 111132323431 its reverse (134323231111), we get a palindrome (245455554542).
The spelling of 111132323431 in words is "one hundred eleven billion, one hundred thirty-two million, three hundred twenty-three thousand, four hundred thirty-one".
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