Base | Representation |
---|---|
bin | 11001010001001100111100… |
… | …111000011110100101111010 |
3 | 112120111020110202212010011121 |
4 | 121101030330320132211322 |
5 | 104031301444324103310 |
6 | 1032205533332415454 |
7 | 32260054531462441 |
oct | 3121147470364572 |
9 | 476436422763147 |
10 | 111133300222330 |
11 | 32457405811091 |
12 | 1056a46547758a |
13 | 4a01a960a10a9 |
14 | 1d62c47c89d58 |
15 | ccac738d60da |
hex | 65133ce1e97a |
111133300222330 has 64 divisors (see below), whose sum is σ = 201101234208768. Its totient is φ = 44217849453120.
The previous prime is 111133300222279. The next prime is 111133300222391. The reversal of 111133300222330 is 33222003331111.
It is a super-2 number, since 2×1111333002223302 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 111133300222295 and 111133300222304.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 20195036359 + ... + 20195041861.
It is an arithmetic number, because the mean of its divisors is an integer number (3142206784512).
Almost surely, 2111133300222330 is an apocalyptic number.
111133300222330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
111133300222330 is a deficient number, since it is larger than the sum of its proper divisors (89967933986438).
111133300222330 is a wasteful number, since it uses less digits than its factorization.
111133300222330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12091.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 111133300222330 its reverse (33222003331111), we get a palindrome (144355303553441).
The spelling of 111133300222330 in words is "one hundred eleven trillion, one hundred thirty-three billion, three hundred million, two hundred twenty-two thousand, three hundred thirty".
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